For example we have

'a' -> 1

'b' -> 2

..

'z' -> 26

 

By given "12", we can decode the string to give result "ab" or 'L', 2 ways to decode, your function should return 2 as an answer.

 

Now asking by given "1246", what should be the return number; 

 

The thinking process is somehow like this:

by given "1" -> we got 'a'

by given "" -> we got ""

by given "12345" -> 'a' + decode('2345') or 'L' + decode('345'), therefore number of ways to decode "12345"is the same of decode(2345)+decode(345).

 

Somehow we can see that this is a recursion task, therefore we can use Dynamice Programming + memo way to solve the problem.

const data = "1246";function num_ways(data) {  // k : count from last to beginning  function helper(data, k, memo) {    if (k === 0) {      // if k equals 0, mean only one single digital number left      // means there must be one char      return 1;    }    if (data === "") {      // if data equals empty, then return 1      return 1;    }    if (memo[k] != null) {      return memo[k];    }    const start = data.length - k;    if (data[start] === "0") {      // if sth start as 0, then no char      return 0;    }    let result = helper(data, k - 1, memo);    if (k >= 2 && parseInt(data.slice(start, start + 2), 10) <= 26) {      result += helper(data, k - 2, memo);    }    memo[k] = result;    return result;  }  let memo = [];  return helper(data, data.length, memo);}const res = num_ways(data);console.log(res); // 3